Finalizing questions and generating report

This commit is contained in:
Noah L. Schrick 2022-09-26 15:57:31 -05:00
parent 0a37b219fc
commit 83daa61841
3 changed files with 182 additions and 0 deletions

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Schrick-Noah_Exam-1.sql Normal file
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/* *** EX1-QACS.A *** */
SELECT *
FROM CUSTOMER
;
SELECT *
FROM ITEM
;
SELECT *
FROM SALE
;
SELECT *
FROM SALE_ITEM
;
/* *** EX1-QACS.B *** */
SELECT LastName, FirstName, Phone
FROM CUSTOMER
;
/* *** EX1-QACS.C *** */
SELECT LastName, FirstName, Phone
FROM CUSTOMER
WHERE FirstName LIKE 'John'
;
/* *** EX1-QACS.D *** */
SELECT c.LastName, c.FirstName, c.Phone, s.SaleDate, s.Total
FROM CUSTOMER c, SALE s
WHERE c.CustomerID = s.CustomerID AND s.Total > 100
;
/* *** EX1-QACS.E *** */
SELECT LastName, FirstName, Phone
FROM CUSTOMER
WHERE FirstName LIKE 'D%'
;
/* *** EX1-QACS.F *** */
SELECT LastName, FirstName, Phone
FROM CUSTOMER
WHERE LastName LIKE '%ne%'
;
/* *** EX1-QACS.G *** */
SELECT LastName, FirstName, Phone
FROM CUSTOMER
WHERE PHONE LIKE '%56_'
;
/* *** EX1-QACS.H *** */
SELECT MAX(Total) AS MaxSalesTotal, MIN(Total) AS MinSalesTotal
FROM SALE
;
/* *** EX1-QACS.I *** */
SELECT AVG(Total) AS AvgSalesTotal
FROM SALE
;
/* *** EX1-QACS.J *** */
SELECT COUNT(*) AS NumCustomers
FROM CUSTOMER
;
/* *** EX1-QACS.K *** */
SELECT LastName, FirstName
FROM CUSTOMER
GROUP BY LastName, FirstName
;
/* *** EX1-QACS.L *** */
SELECT LastName, FirstName, COUNT(*) AS NameCombo
FROM CUSTOMER
GROUP BY LastName, FirstName
;
/* *** EX1-QACS.M *** */
SELECT LastName, FirstName, Phone
FROM CUSTOMER
WHERE CustomerID IN
(SELECT CustomerID
FROM SALE
WHERE Total > 100
)
ORDER BY LastName ASC, FirstName DESC
;
/* *** EX1-QACS.N *** */
SELECT DISTINCT c.LastName, c.FirstName, c.Phone
FROM CUSTOMER c, SALE s
WHERE c.CustomerID = s.CustomerID AND s.Total > 100
ORDER BY LastName ASC, FirstName DESC
;
/* *** EX1-QACS.O *** */
SELECT DISTINCT c.LastName, c.FirstName, c.Phone
FROM CUSTOMER c JOIN SALE s
ON c.CustomerID = s.CustomerID
WHERE s.Total > 100
ORDER BY LastName ASC, FirstName DESC
;
/* *** EX1-QACS.P *** */
SELECT LastName, FirstName, Phone
FROM CUSTOMER
WHERE CustomerID IN
(SELECT CustomerID
FROM SALE
WHERE SaleID IN
(SELECT SaleID
FROM SALE_ITEM
WHERE ItemID IN
(SELECT ItemID
FROM ITEM
WHERE ItemDescription LIKE 'Desk Lamp'
)
)
)
ORDER BY LastName ASC, FirstName DESC
;
/* *** EX1-QACS.Q *** */
SELECT c.LastName, c.FirstName, c.Phone
FROM CUSTOMER c, SALE s, Sale_ITEM si, ITEM i
WHERE c.CustomerID = s.CustomerID
AND s.SaleID = si.SaleID
AND si.ItemID = i.ItemID
AND i.ItemDescription LIKE 'Desk Lamp'
ORDER BY LastName ASC, FirstName DESC
;
/* *** EX1-QACS.R *** */
SELECT c.LastName, c.FirstName, c.Phone
FROM CUSTOMER c JOIN SALE s ON c.CustomerID = s.CustomerID
JOIN Sale_ITEM si ON s.SaleID = si.SaleID
JOIN ITEM i ON si.ItemID = i.ItemID
WHERE i.ItemDescription LIKE 'Desk Lamp'
ORDER BY LastName ASC, FirstName DESC
;
/* *** EX1-QACS.S *** */
SELECT c.LastName, c.FirstName, c.Phone
FROM CUSTOMER c JOIN SALE s ON c.CustomerID = s.CustomerID
JOIN Sale_ITEM si ON s.SaleID = si.SaleID
WHERE si.ItemID IN
(SELECT ItemID
FROM ITEM
WHERE ItemDescription LIKE 'Desk Lamp'
)
ORDER BY LastName ASC, FirstName DESC
;
/* *** EX1-QACS.T *** */
SELECT c.LastName, c.FirstName, c.Phone
FROM CUSTOMER c JOIN SALE s ON c.CustomerID = s.CustomerID
WHERE s.SaleID IN
(SELECT SaleID
FROM SALE_ITEM
WHERE ItemID IN
(SELECT ItemID
FROM ITEM
WHERE ItemDescription LIKE 'Desk Lamp'
)
)
ORDER BY LastName ASC, FirstName DESC
;
/* *** EX1-QACS.U *** */
SELECT c.LastName, c.FirstName, c.Phone, 'Item' =
CASE
WHEN i.ItemDescription = 'Desk Lamp' THEN i.ItemDescription
ELSE ''
END
FROM CUSTOMER c JOIN SALE s ON c.CustomerID = s.CustomerID
JOIN Sale_ITEM si ON s.SaleID = si.SaleID
JOIN ITEM i ON si.ItemID = i.ItemID
ORDER BY 'Item' DESC, LastName ASC, FirstName DESC
;