noah/QM-7093-Case-Study-2
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Finalized sql

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This commit is contained in:
Noah L. Schrick 2022-09-12 22:01:55 -05:00
parent 00d5f5e2d4
commit 65494a1af4
1 changed files with 86 additions and 1 deletions
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87
Schrick-Noah_Case-Study-2.sql
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@ -11,7 +11,7 @@ SELECT LastName, FirstName, Phone
/* *** CS2-C *** */ /* *** CS2-C *** */
SELECT LastName, FirstName, Phone SELECT LastName, FirstName, Phone
FROM CUSTOMER FROM CUSTOMER
WHERE FirstName LIKE 'Nikki' WHERE FirstName = 'Nikki'
; ;
/* *** CS2-D *** */ /* *** CS2-D *** */
@ -39,30 +39,115 @@ SELECT LastName, FirstName, Phone
; ;
/* *** CS2-H *** */ /* *** CS2-H *** */
SELECT MAX(TotalAmount) AS MaxTotalAmount,
MIN(TotalAmount) AS MinTotalAmount
FROM INVOICE
;
/* *** CS2-I *** */ /* *** CS2-I *** */
SELECT AVG(TotalAmount) AS AvgTotalAmount
FROM INVOICE
;
/* *** CS2-J *** */ /* *** CS2-J *** */
SELECT COUNT(CustomerID) AS TotalCustomers
FROM CUSTOMER
;
/* *** CS2-K *** */ /* *** CS2-K *** */
SELECT LastName, FirstName
FROM CUSTOMER
GROUP BY LastName, FirstName
;
/* *** CS2-L *** */ /* *** CS2-L *** */
SELECT LastName, FirstName,
COUNT(*) AS LastFirstNameCombo
FROM CUSTOMER
GROUP BY LastName, FirstName
;
/* *** CS2-M *** */ /* *** CS2-M *** */
SELECT LastName, FirstName, Phone
FROM CUSTOMER
WHERE CustomerID IN
(SELECT CustomerID
FROM INVOICE
WHERE TotalAmount > 100.0
)
ORDER BY LastName ASC, FirstName DESC
;
/* *** CS2-N *** */ /* *** CS2-N *** */
SELECT Cust.LastName, Cust.FirstName, Cust.Phone
FROM CUSTOMER AS Cust, Invoice AS Inv
WHERE Inv.TotalAmount > 100.00
ORDER BY LastName ASC, FirstName DESC
;
/* *** CS2-O *** */ /* *** CS2-O *** */
SELECT LastName, FirstName, Phone
FROM CUSTOMER JOIN INVOICE
ON CUSTOMER.CustomerID = INVOICE.CustomerID
WHERE TotalAmount > 100.00
ORDER BY LastName ASC, FirstName DESC
;
/* *** CS2-P *** */ /* *** CS2-P *** */
SELECT LastName, FirstName, Phone
FROM CUSTOMER
WHERE CUSTOMER.CustomerID IN
(SELECT CustomerID
FROM INVOICE
WHERE InvoiceNumber IN
(SELECT InvoiceNumber
FROM INVOICE_ITEM
WHERE Item LIKE 'Dress Shirt'
)
)
ORDER BY LastName ASC, FirstName DESC
;
/* *** CS2-Q *** */ /* *** CS2-Q *** */
SELECT LastName, FirstName, Phone
FROM CUSTOMER, INVOICE, INVOICE_ITEM
WHERE INVOICE_ITEM.Item LIKE 'Dress Shirt'
ORDER BY LastName ASC, FirstName DESC
;
/* *** CS2-R *** */ /* *** CS2-R *** */
SELECT LastName, FirstName, Phone
FROM CUSTOMER
JOIN INVOICE ON CUSTOMER.CustomerID=INVOICE.CustomerID
JOIN INVOICE_ITEM ON INVOICE.InvoiceNumber=INVOICE_ITEM.InvoiceNumber
WHERE Item Like 'Dress Shirt'
ORDER BY LastName ASC, FirstName DESC
;
/* *** CS2-S *** */ /* *** CS2-S *** */
SELECT C.LastName AS CustomerLastName, C.FirstName AS CustomerFirstName, R.LastName AS ReferredByLastName, R.FirstName AS ReferredByFirstName
FROM CUSTOMER C
LEFT JOIN CUSTOMER R ON R.CustomerID=C.ReferredBy
;
/* *** CS2-T *** */ /* *** CS2-T *** */
SELECT LastName, FirstName, Phone
FROM CUSTOMER
JOIN INVOICE ON CUSTOMER.CustomerID=INVOICE.CustomerID
WHERE INVOICE.InvoiceNumber IN (SELECT InvoiceNumber FROM INVOICE_ITEM WHERE Item LIKE 'Dress Shirt')
ORDER BY LastName ASC, FirstName DESC
;
/* *** CS2-U *** */ /* *** CS2-U *** */
SELECT C.LastName, C.FirstName, C.Phone,
"Total Amount" =
CASE
WHEN T.Item = 'Dress Shirt' THEN I.TotalAmount
ELSE NULL
END
FROM CUSTOMER C, INVOICE I, INVOICE_ITEM T
WHERE C.CustomerID = I.CustomerID
AND I.InvoiceNumber = T.InvoiceNumber
ORDER BY "Total Amount" ASC, LastName ASC, FirstName DESC
;